makepkg: output the name of the package being created

Although it should be currently quite obvious what package is being
created when "Creating package..." is printed, it will not be in the
future when a debug package is potentially created too.  Also, given
$pkgname is always correctly set when split packaging now, we no
longer need to pass that around.

Signed-off-by: Allan McRae <allan@archlinux.org>

scripts/makepkg.sh.in

@@ -1719,7 +1719,7 @@ write_pkginfo() {
 		echo "# using $(fakeroot -v)"
 	fi
 	echo "# $(LC_ALL=C date -u)"
-	printf "pkgname = %s\n" "$1"
+	printf "pkgname = %s\n" "$pkgname"
 	(( SPLITPKG )) && echo pkgbase = $pkgbase
 	echo "pkgver = $(get_full_version)"
 	printf "pkgdesc = %s\n" "$pkgdesc"
@@ -1790,18 +1790,11 @@ create_package() {
 	check_package
 
 	cd_safe "$pkgdir"
-	msg "$(gettext "Creating package...")"
-
-	local nameofpkg
-	if [[ -z $1 ]]; then
-		nameofpkg="$pkgname"
-	else
-		nameofpkg="$1"
-	fi
+	msg "$(gettext "Creating package \"%s\"...")" "$pkgname"
 
 	pkgarch=$(get_pkg_arch)
 
-	write_pkginfo $nameofpkg > .PKGINFO
+	write_pkginfo > .PKGINFO
 
 	local comp_files=('.PKGINFO')
 
@@ -1821,7 +1814,7 @@ create_package() {
 	msg2 "$(gettext "Compressing package...")"
 
 	local fullver=$(get_full_version)
-	local pkg_file="$PKGDEST/${nameofpkg}-${fullver}-${pkgarch}${PKGEXT}"
+	local pkg_file="$PKGDEST/${pkgname}-${fullver}-${pkgarch}${PKGEXT}"
 	local ret=0
 
 	[[ -f $pkg_file ]] && rm -f "$pkg_file"
@@ -2338,7 +2331,7 @@ run_split_packaging() {
 		backup_package_variables
 		run_package $pkgname
 		tidy_install
-		create_package $pkgname
+		create_package
 		restore_package_variables
 		pkgdir="${pkgdir%/*}"
 	done